Question

Simplify the following:
$\frac{9}{3}÷\frac{4}{6}\times \frac{13}{18}-\frac{3}{5}=$ $x\frac{13}{20}$. Find x.

Answer 1

For the value of$X$ we solve the given equation

$\Rightarrow \frac{9}{3}÷\frac{4}{6}\times \frac{13}{18}-\frac{3}{5}=x\frac{13}{20}$

$\Rightarrow \frac{9}{3}\times \frac{6}{4}\times \frac{13}{18}-\frac{3}{5}=\frac{20x+13}{20}$

$\Rightarrow \frac{13}{4}-\frac{3}{5}=\frac{20x+13}{20}$

$\Rightarrow \frac{65-12}{20}=\frac{20x+13}{20}\left[L.C.Mof4,5\right]$

$\Rightarrow 20x+13=53$

$\Rightarrow 20x=53-13$

$\Rightarrow 20x=40$

$\Rightarrow x=\frac{40}{20}=2$

$\therefore x=2$