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Byju's Answer
Standard X
Mathematics
Nature of Roots
Simplify the ...
Question
Simplify the following expression:
cos
0
+
cos
π
2
+
cos
2
π
7
+
cos
3
π
7
+
cos
4
π
7
+
cos
5
π
7
+
cos
6
π
7
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Solution
cos
0
°
+
cos
π
2
+
cos
2
π
7
+
cos
3
π
7
+
cos
4
π
7
+
cos
5
π
7
+
cos
6
π
7
=
1
+
0
+
cos
6
π
7
+
2
cos
π
2
cos
3
π
14
+
2
cos
π
2
cos
π
14
=
1
+
cos
6
π
7
=
2
cos
2
3
π
7
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1
Similar questions
Q.
The value of
cos
0
+
cos
π
7
+
cos
2
π
7
+
cos
3
π
7
+
cos
4
π
7
+
cos
5
π
7
+
cos
6
π
7
=
Q.
cos
π
7
+
cos
2
π
7
+
cos
3
π
7
+
cos
4
π
7
+
cos
5
π
7
+
cos
6
π
7
=
Q.
cos
π
7
+
cos
2
π
7
+
cos
3
π
7
+
cos
4
π
7
+
cos
5
π
7
+
cos
6
π
7
+
cos
7
π
7
=
Q.
The value of
cos
π
7
+
cos
2
π
7
+
cos
3
π
7
+
cos
4
π
7
+
cos
5
π
7
+
cos
6
π
7
+
cos
7
π
7
is
Q.
Match the column
List I
List II
A.
cos
20
∘
+
cos
80
∘
−
√
3
cos
50
∘
1.
−
1
B.
cos
0
∘
+
cos
π
7
+
cos
2
π
7
+
cos
3
π
7
+
cos
4
π
7
+
cos
5
π
7
+
cos
6
π
7
2.
−
3
4
C.
cos
20
∘
+
cos
40
∘
+
cos
60
∘
+
4
cos
10
∘
cos
20
∘
cos
30
∘
3.
1
D.
cos
20
∘
cos
100
∘
+
cos
100
∘
cos
140
∘
−
cos
140
∘
cos
200
∘
4.
0
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