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Byju's Answer
Standard VII
Mathematics
Changing Scale (Including Flags)
Simplify the ...
Question
Simplify the following expression:
1
a
+
1
b
+
c
1
a
−
1
b
+
c
(
1
+
b
2
+
c
2
−
a
2
2
b
c
)
(
a
+
b
+
c
)
−
2
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Solution
1
a
+
1
b
+
c
1
a
−
1
b
+
c
=
a
+
b
+
c
b
+
c
−
a
1
+
b
2
+
c
2
−
a
2
2
b
c
=
b
2
+
c
2
+
2
b
c
−
a
2
2
b
c
=
(
a
+
b
+
c
)
(
b
+
c
−
a
)
2
b
c
1
a
+
1
b
+
c
1
a
−
1
b
+
c
(
1
+
b
2
+
c
2
−
a
2
2
b
c
)
(
a
+
b
+
c
)
−
2
=
a
+
b
+
c
b
+
c
−
a
×
(
a
+
b
+
c
)
(
b
+
c
−
a
)
2
b
c
×
1
(
a
+
b
+
c
)
2
=
1
2
b
c
Suggest Corrections
0
Similar questions
Q.
If
a
=
1
,
b
=
−
1
and
c
=
0
, find the value of expression
(
a
2
−
b
2
)
+
(
c
2
−
b
2
)
+
(
a
2
−
c
2
)
Q.
If three real numbers
a
,
b
,
c
none of which is zero are related by:
a
2
=
b
2
+
c
2
−
2
b
c
√
1
−
a
2
,
b
2
=
c
2
+
a
2
−
2
c
a
√
1
−
b
2
,
c
2
=
a
2
+
b
2
−
2
a
b
√
1
−
c
2
, then prove that
a
=
c
√
1
−
b
2
+
b
√
1
−
c
2
.
Q.
If
a
=
1
,
b
=
−
1
and
c
=
0
, find the value of expression
a
2
+
b
2
+
c
2
Q.
If
a
+
b
+
c
=
0
then
1
b
2
+
c
2
−
a
2
+
1
c
2
+
a
2
−
b
2
+
1
a
2
+
b
2
−
c
2
is equal to
Q.
a
2
+ b
2
+ c
2
- ab - bc - ca equals:
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Standard VII Mathematics
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