Question

Simplify this$\frac{\sqrt{28}}{\sqrt{343}}$ , and find the type of number obtained.

• A. real number
• B. rational number
• C. irrational number
• D. None of the above

Answer 1

Answer: (A), (B)

real number
rational number

$\frac{\sqrt{28}}{\sqrt{343}}=\frac{\sqrt{4\times 7}}{\sqrt{49\times 7}}$

$=\frac{2\times \sqrt{7}}{7\times \sqrt{7}}$

$=\frac{2}{7},$ which is a rational number.

All rational numbers are real numbers.