Simplify: $x^{a + b} x^{b + c} x^{c + a}$

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Solution

$x^{a + b} x^{b + c} x^{c + a}$

$= x^{a + b + b + c + c + a}$

$= x^{2 a + 2 b + 2 c}$

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Similar questions

\frac{x^{a + b} \times x^{b + c} \times x^{c + a}}{(x^{a} \times x^{b} \times x^{c})}

\frac{1}{1 + x^{b - a} + x^{c - a}} + \frac{1}{1 + x^{a - b} + x^{c - b}} + \frac{1}{1 + x^{a - c} + x^{b - c}}

{(\begin{matrix} \frac{x^{a}}{x^{b}} \end{matrix})}^{a + b} \times {(\begin{matrix} \frac{x^{b}}{x^{c}} \end{matrix})}^{b + c} \times {(\begin{matrix} \frac{x^{c}}{x^{a}} \end{matrix})}^{c + a}

{(\begin{matrix} \frac{x^{b}}{x^{c}} \end{matrix})}^{(b + c - a)} . {(\begin{matrix} \frac{x^{c}}{x^{a}} \end{matrix})}^{(c + a - b)} . x {(\begin{matrix} \frac{x^{a}}{x^{b}} \end{matrix})}^{(a + b - c)} = ?

\frac{1}{1 + x^{a - b}} + \frac{1}{1 + x^{b - a}} = 1

\frac{1}{1 + x^{b - a} + x^{c - a}} + \frac{1}{1 + x^{a - b} + x^{c - b}} + \frac{1}{1 + x^{b - c} + x^{a - c}} = 1

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