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B
14cosθsin4θ
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C
12sin22θ
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D
14sinθsin4θ
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Solution
The correct option is D14sinθsin4θ Given:sin2θcos3θ−sin4θcosθ=sin2θcosθ(cos2θ−sin2θ)=sin2θcosθcos2θ=12sinθsinθcosθcos2θ=12sinθsin2θcos2θ=14sinθsin4θ
Hence, The correct answer is option D.