$sin 2 A = 2 sin A i s t r u e, w h e n A =$

Open in App

Solution

$sin 2 A = 2 sin A (Given)$
$\Rightarrow 2 sin A cos A = 2 sin A$
$\Rightarrow cos A = 1$
$\Rightarrow A = 0$
Hence $sin 2 A = 2 sin A$ if $A = 0$

Suggest Corrections

Similar questions

| t a n A | < 1,

| A |

\frac{\sqrt{1 + s i n 2 A} + \sqrt{1 - s i n 2 A}}{\sqrt{1 + s i n 2 A} - \sqrt{1 - s i n 2 A}}

\frac{\sqrt{1 + sin 2 A} + \sqrt{1 - sin 2 A}}{\sqrt{1 + sin 2 A} - \sqrt{1 - sin 2 A}}

| tan A | < 1

| A |

Prove it:

Cos²A-cos²A=sin²A-sin²A

{sin}^{2} A + {sin}^{2} (A + B) - 2 sin A cos B sin (A + B)

B = 45^{\circ}

\frac{{sin}^{2} A}{{cos}^{2} A} + \frac{{cos}^{2} A}{{sin}^{2} A} = {sec}^{2} A c o s e c^{2} A - 2

Join BYJU'S Learning Program