Question

$\sin ({45}^{\circ }+\theta )-\cos ({45}^{\circ }-\theta )=$

• A. $2\cos \theta$
• B. $2\sin \theta$
• C. $0$
• D. $1$

Answer 1

The correct option is C $0$

Given,

$\sin ({45}^o+\theta )-\cos \left({45}^o-\theta \right)$

$=\sin ({45}^o+\theta )-\sin ({90}^o-\left({45}^o-\theta \right))$

$=\sin ({45}^o+\theta )-\sin ({45}^o+\theta )$

$=0$

so $0$ is the answer