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Question

sinπn+sin3πn+sin5πn+ upto n terms is equal to

A
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3
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D
0
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Solution

The correct option is A 0
sinπn+sin3πn+sin5πn+ upto n terms
=sinn2π2nsin2π2nsin⎜ ⎜2πn+(n1)2πn2⎟ ⎟
=sinπsinπnsin(2π+2nπ2π2n)
=sin2πsinπn=0

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