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Question

The value of sinπn+sin3πn+sin5πn+.....ton terms is equal to

A
1
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B
0
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C
n2
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D
None of these
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Solution

The correct option is B 0
The value of sinπn+sin3πn+sin5πn+...+sin(2n+1)πn
=sin((2n+1)2πn.)sin(2πn)sin(πn+2n2πn)=0

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