Question

sin(n + 1)x sin ( n+2 )x + cos(n+1)x cos (n+2)x = cos x

Answer 1

We have

cos(n+1)xcos(n+2)x + sin(n+1)xsin(n+2)x

it is from the identity

cos(a-b) = cosa * cosb + sina * sinb

here a= (n+1)x and b= (n+2)x

so,

= cos((n+1)x-(n+2)x)

= cos(nx+x-nx-2x)

= cos(-x)

= cosx { since cos(-x) = cosx }