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Question

sin θ1+cos θis equal to

(a) 1+cos θsin θ
(b) 1-cos θcos θ
(c) 1-cos θsin θ
(d) 1-sin θcos θ

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Solution

The given expression is .

Multiplying both the numerator and denominator under the root by , we have

Therefore, the correct option is (c).


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