sinθ = 510 = 12 As we know that, sin^2θ + cos^2θ = 1 ⇒cosθ = √(1 sin^2θ) ⇒cosθ = √(1 ( 12)^2) = √(34) = √(3)2 ...

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Range of Trigonometric Ratios from 0 to 90 Degrees

sinθ=[510] fi...

Question

$sin θ = [\frac{5}{10}]$ find $cos$

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Solution

$sin θ = \frac{5}{10} = \frac{1}{2}$
As we know that,
${sin}^{2} θ + {cos}^{2} θ = 1$
$\Rightarrow cos θ = \sqrt{1 - {sin}^{2} θ}$
$\Rightarrow cos θ = \sqrt{1 - {(\frac{1}{2})}^{2}} = \sqrt{\frac{3}{4}} = \frac{\sqrt{3}}{2}$

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