Sin y-x sin -y- then d y-d x isA- sin-sin 2-yB- sin 2-y-sin-C- sin-sin 2-yD- sin 2-y-sin-

The correct option is B y=s sin(a+y) ⇒ y_1=sin(a+y)+x cos(a+y)y_1 ⇒ y_1=sin(a+y)/1 x cos(a+y) Here replace 'X' value ...

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Implicit Differentiation

sin y=x sin α...

Question

$s i n y = x s i n (α + y), t h e n \frac{d y}{d x} i s$

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Similar questions

If sin $α$ +sin $β$ +sin $γ$ =0= cos $α$ +cos $β$ +cos $γ$ ,

value of $s i n^{2}$ $α$ + $s i n^{2}$ $β$ + $s i n^{2}$ $γ$

cos α + cos β + cos α = 0 = sin α + sin β + sin α

{cos}^{2} α + {cos}^{2} β + {cos}^{2} α = \frac{3}{α} = {sin}^{2} α + {sin}^{2} β + {sin}^{2} α

sin α = sin 2 α .

\frac{s i n α}{a} = \frac{c o s α}{b}, t h e n a s i n 2 α + b c o s 2 α

c o s (α + β) = 0

s i n (α - β)

c o s β

c o s 2 β

s i n α

s i n 2 α

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