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Question

(sinx+cosx)2+cos2(π4x)

A
[0,1]
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B
[0,2]
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C
[1,2]
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D
[0,3]
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Solution

The correct option is D [0,3]
Let f(x)=(sinx+cosx)2+cos2(π4x)
=1+2sinxcosx+[cos2(π4x)+12]
=32+sin2x+sin2x2
f(x)=32+32sin2x
Range of f(x)ϵ[3232,32+32]
ϵ[0,3]

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