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Question

Six capacitors each of capacitance of 2μF are connected as shown in the figure. The effective capacitance between A and B is
1296924_0a096252cc7049dc9ba30858796a0126.png

A
12μF
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B
83μF
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C
3μF
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D
6μF
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Solution

The correct option is A 12μF
If you carefully see the circuit, A is the common point for all capacitor for one side plate and B is common for other side plate of all capacitor. Thus they are in parallel configuration.
Therefore CAB=nC=6×2=12μF

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