Question

Six hundred millilitres of ozonised oxygen at $STP$ was found to weigh 1 $g$. What is the volume of ozone in the ozonized oxygen?

• A. 200 $ml$
• B. 150 $ml$
• C. 100 $ml$
• D. 50 $ml$

Answer 1

The correct option is A 200 $ml$

Let the volume of $O_3$ be $x$ ml
Volume of $O_2$ present $=(600-x)ml$
22400 mI of $O_3$ and $O_2$ at $STP$ will weigh 48 and 32 $g$, respectively
The weight of $x$ $ml$ of $O_3$ = $\frac{x\times 48}{22400}g$
The weight of $(600-x)ml$ of $O_2=\frac{(600-x)}{22400}\times 32$
Total weight of ozonised $O_2$ (600 $ml$) is
$\frac{48x}{22400}+\frac{(600-x)\times 32}{22400}=1.0$
$\therefore x=200ml$