Question

Six years hence a man's age will be three times the age of his son and three years ago he was nine times as old as his son. Find their present ages.

Answer 1

Let the present age of the man be x years and the present age of his son be y years.

After 6 years, the man’s age will beyears and son’s age will beyears. Thus using the given information, we have

Before 3 years, the age of the man wasyears and the age of son’s wasyears. Thus using the given information, we have

So, we have two equations

Here x and y are unknowns. We have to solve the above equations for x and y.

By using cross-multiplication, we have

Hence, the present age of the man isyears and the present age of son isyears.