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Byju's Answer
Standard XII
Chemistry
Concentration Terms
SnCl2 can be ...
Question
S
n
C
l
2
can be volumetrically determined by titration with
F
e
C
l
3
2
F
e
3
+
+
S
n
2
+
→
2
F
e
2
+
+
S
n
4
+
K
C
N
S
gives which colour with
F
e
3
+
ion
:
A
Red
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B
White
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C
Black
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D
Yellow
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Solution
The correct option is
A
Red
K
C
N
S
gives a deep red colouration with
F
e
3
+
due to the formation of
F
e
(
S
C
N
)
3
.
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Similar questions
Q.
Determine the equilibrium constant of the following reaction at
298
K
:
2
F
e
3
+
+
S
n
2
+
→
2
F
e
2
+
+
S
n
4
+
(Given:
E
∘
S
n
4
+
/
S
n
2
+
=
0.15
v
o
l
t
;
E
∘
F
e
3
+
/
F
e
2
+
=
0.771
v
o
l
t
).
Q.
The standard electrode potentials(reduction) of
F
e
3
+
,
F
e
2
+
/
P
t
and
S
n
4
+
,
S
n
2
+
/
P
t
are
+
0.77
V
and
0.15
V
respectively at
25
o
C
. The standard EMF of the following reaction is:
S
n
4
+
+
2
F
e
2
+
→
S
n
2
+
+
2
F
e
3
+
Q.
Write the following ionic equation in the molecular form if the reactants are chlorides.
2
F
e
3
+
+
S
n
2
+
→
2
F
e
2
+
+
S
n
4
+
.
Q.
What is `A' in the following reaction
2
F
e
3
+
(
a
q
)
+
S
n
2
+
(
a
q
)
→
2
F
e
2
+
(
a
q
)
+
A
Q.
Assertion :
F
e
C
l
3
can be reduced to
F
e
C
l
2
by
S
n
C
l
2
as well as by the addition of
S
n
into it. Reason: This reaction is possible since
S
n
4
+
is more stable than
S
n
2
+
(inert-pair effect)Also,
F
e
C
l
3
solution is acidic due to hydrolysis.
S
n
added reacts with
H
C
l
forming nascent hydrogen that can reduce
F
e
C
l
3
to
F
e
C
l
2
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