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Balancing Chemical Equations by Partial Equation Method

...SO2g+....O...

Question

$. . . S O_{2} (g) + . . . . O_{2} (g) \to . . . S O_{3} (g)$
According to the above unbalanced equation, how many moles of $S O_{2} (g)$ will react completely with 1 mole of $O_{2} (g)$ ?

0.5

mol

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1

mol

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2

mol

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3

mol

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4

mol

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Solution

The correct option is C $2$ mol
The unbalanced chemical equation is $S O_{2} (g) + O_{2} (g) \to S O_{3} (g)$
In this equation, S atoms are already balanced. Balance O atoms.

$S O_{2} (g) + \frac{1}{2} O_{2} (g) \to S O_{3} (g)$

This is the balanced chemical equation.
1 mole of $S O_{2} (g)$ completely reacts with $\frac{1}{2}$ moles of $O 2 (g)$ .
Hence, 2 moles of $S O_{2} (g)$ will completely react with 1 mole of $O_{2} (g)$ .

Hence, the correct option is $C$

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