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Question

SO2 reduces MnO4 to Mn2+. Number of electrons involved in the reduction of MnO4 to Mn2+ is :

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Solution

Let x be the oxidation no. of Mn in MnO4

x+4×(2)=1

x=+7
The oxidation no. of Mn in MnO4 is +7.
The oxidation number of Mn in Mn2+ is +2.

Thus oxidation no. of manganese changes from +7 to +2.Number of electrons involved in the reduction of MnO4 to Mn2+ is 5.

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