Question

Sodium metal crystallizes as a body centred cubic lattice with the cell edge 4.29 $\stackrel{\circ }{A}$. What is the radius of sodium atom

• A. $1.857\times {10}^{-8}$
• B. $2.371\times {10}^{-7}$
• C. $3.817\times {10}^{-8}$
• D. $9.312\times {10}^{-7}$

Answer 1

The correct option is A $1.857\times {10}^{-8}$

Radius of Na (if bcc lattice) $=\frac{\sqrt{3}\times 4.29}{4}=1.8574\stackrel{\circ }{A}=1.8574\times {10}^{-5}cm$