Sodium metal crystallizes as a body centred cubic lattice with the cell edge 4.29 $\circ A$ . What is the radius of sodium atom

1.857 x 10^-8

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2.371 x 10^-7

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3.817 x 10^-8

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9.312 x 10^-7

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Solution

The correct option is A 1.857 x 10^-8
Radius of Na (if bcc lattice) $= \frac{\sqrt{3} \times 4.29}{4} = 1.8574 \circ A = 1.8574 \times 10^{- 5} c m$

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Sodium metal crystallises in a body-centred cubic lattice with the cell edge a = 4.29 Å . What is the radius of the sodium atom?

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