Question

Sodium nitrate decomposes above ${800}^{o}C$ to give:

• A. $N_2$
• B. $O_2$
• C. $N{O}_2$
• D. $N{a}_{2}O$

Answer 1

Answer: (A), (B), (D)

$N_2$
$N{a}_{2}O$
$O_2$

$2NaN{O}_3\stackrel{\Delta }{⟶}2NaN{O}_2+O_2\uparrow$

When sodium nitrate decomposes above $\approx {800}^{o}C$,

$2NaN{O}_3\stackrel{{800}^{o}C}{⟶}N{a}_{2}O+N_2\uparrow +\frac{5}{2}{O}_2\uparrow$

Hence options A,B & D are correct.