Question

Sodium nitrate decomposes above 800°C and does not give:

• A. N₂
• B. O₂
• C. NO₂
• D. Na₂O

Answer 1

The correct option is A

N₂

$NaN{O}_3$ decomposes on heating above ${800}^0$ C to give $O_2$

$2NaN{O}_3\to N{a}_{2}O+2N{O}_2+\frac{1}{2}{O}_2$