Sodium nitrate on reduction with $Z n$ in presence of $N a O H$ solution produces ${N H}_{3}$ . Mass of sodium nitrate absorbing 1 mole of electron will be:

7.75

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10.625

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9.875

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 10.625
Required equation is given below,
$Z n + 2 {O H}^{-} ⟶ {Z n O}_{2}^{2 -} + {2 H}^{+} + {2 e}^{-}$
${N O}_{3}^{-} + {8 H}^{+} {8 e}^{-} ⟶ {O H}^{-} + 2 H_{2} O + {N H}_{3}$
From the above equation
$∵$ 8 moles of electron absorbed by 85g of ${N a N O}_{3}$
$∴$
1 mole of electron absorbed by $\frac{85}{8} g$ of ${N a N O}_{3}$
$= 10.625 g$

Suggest Corrections

Similar questions

Q. A metal nitrate on reaction with excess sodium hydroxide solution gives a white precipitate but it rapidly turns brown on adding bromine water. Aqueous solution of metal nitrate produces a pink precipitate with disodium hydrogen phosphate solution in the presence of ammonia. The cation is:

Q. What mass of silver nitrate will react with

5.85 g

of sodium chloride to produce

14.35 g

of silver chloride and

8.5 g

of sodium nitrate. If the law of conservation of mass is true?

Sodium chloride (

N a C l

) reacts with silver nitrate (

A g N O_{3}

) to produce silver chloride (

A g C l

) and sodium nitrate (

N a N O_{3}

). The weight of silver nitrate reacts with 1 mol of sodium chloride is _________ .

Q. Describe in each case, one chemical test that would enable you to distinguish between the following pairs of chemicals. Describe what happens with each chemical or state 'no visible reaction'.
(i) Sodium chloride solution and sodium nitrate solution.
(ii) Sodium sulphate solution and sodium chloride solution.
(iii) Calcium nitrate solution and zinc nitrate solution.

Choose the correct answer:
Dilute sulphuric acid will produce a white precipitate when added to a solution of:
(a) Copper nitrate
(b) Zinc nitrate
(c) Lead nitrate
(d) Sodium nitrate

Join BYJU'S Learning Program

Sodium nitrate on reduction with Zn in presence of NaOH solution produces NH3. Mass of sodium nitrate absorbing 1 mole of electron will be:

The correct option is B 10.625Required equation is given below,Zn+2OH−⟶ZnO2−2+2H++2e−NO−3+8H+8e−⟶OH−+2H2O+NH3From the above equation∵ 8 moles of electron absorbed by 85g of NaNO3∴ 1 mole of electron absorbed by 858g of NaNO3=10.625g

Sodium nitrate on reduction with $Z n$ in presence of $N a O H$ solution produces ${N H}_{3}$ . Mass of sodium nitrate absorbing 1 mole of electron will be: