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Intensity in Photon Model

Sodium surfac...

Question

Sodium surface is illuminated by ultraviolet and visible radiation successively and the stopping potential determined. The stopping potential is

A

Infinite in both cases

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B

Greater with ultraviolet light

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C

Equal in both cases

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D

Greater with visible light

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Solution

The correct option is B
Greater with ultraviolet light

Therefore, smaller the value of λ, greater will be the energy of incident radiation .Since wavelength of ultraviolet radiation is less than that of visible light, stopping potential will be greater in case of ultraviolet light.

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