Question

Sodium surface is illuminated with ultraviolet light and visible radiation successively and the stopping potentials are determined. Then the potential

• A. Is equal in both the cases
• B. Greater for ultraviolet light
• C. More for visible light
• D. Varies randomly

Answer 1

The correct option is B Greater for ultraviolet light

$\lambda$ for U.V is less than $\lambda$ for visible light

$\nu$ for U.V is greather than $\nu$ for visible light

$\therefore$ potential is greater for U.V light.

as $K.E\alpha \frac{1}{\lambda }$