Question

Solubility of $AgBr$ will be minimum in:

• A. pure water
• B. $0.1M{CaBr}_2$
• C. $0.1MNaBr$
• D. $0.1M{AgNO}_3$

Answer 1

The correct option is C $0.1MNaBr$

Solution:- (C) $0.1MNaBr$

$AgBr\rightleftharpoons {Ag}^{+}+{Br}^{-}$

To decrease the ${Ag}^{+}$ in a solution of $AgBr$, we can add excess ${Br}^{-}$ ions in the form of a soluble salt such as $NaBr$. This excess puts a stress on the equilibrium system which adjusts itself by shifting left. As it consumes ${Br}^{-}$ ions and forms $AgBr$.

Hence the solubility of $AgBr$ will be minimum in $0.1MNaBr$.