Solubility of oxygen gas in water follows Henry's law. When the solubility is plotted against partial pressure at a definite temperature we get following plot.
Which of the following sequences of temperatures is correct ?

T_{1} = T_{2} = T_{3} = T_{4}

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T_{1} > T_{2} > T_{3} > T_{4}

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T_{1} < T_{2} < T_{3} < T_{4}

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T_{1} > T_{2} < T_{3} > T_{4}

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Solution

The correct option is A $T_{1} = T_{2} = T_{3} = T_{4}$

The solubility is plotted against partial pressure at a definite temperature was get plotted so the temparature at all cases is same
So $T_{1} = T_{2} = T_{3} = T_{4}$ .
Hence option A is correct.

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Solubility of oxygen gas in water follows Henry's law. When the solubility is plotted against partial pressure at a definite temperature we get following plot. Which of the following sequences of temperatures is correct ?

The correct option is A T1=T2=T3=T4 The solubility is plotted against partial pressure at a definite temperature was get plotted so the temparature at all cases is same So T1=T2=T3=T4.Hence option A is correct.

Solubility of oxygen gas in water follows Henry's law. When the solubility is plotted against partial pressure at a definite temperature we get following plot.
Which of the following sequences of temperatures is correct ?

The correct option is A $T_{1} = T_{2} = T_{3} = T_{4}$

The solubility is plotted against partial pressure at a definite temperature was get plotted so the temparature at all cases is same
So $T_{1} = T_{2} = T_{3} = T_{4}$ .
Hence option A is correct.