Question

Solution of $\sqrt{9x^2+6x+1}<5-x$ is

• A. $x<1$ or $x>-3$
• B. $x$ $\le$ $1$ or $x$ $\ge$ $-3$
• C. $x>1$ or $x<3$
• D. None

Answer 1

The correct option is A $x<1$ or $x>-3$

$9x^2+6x+1<25+x^2-10x$

$\Rightarrow 8x^2+16x-24<0$

$\Rightarrow x^2+2x-3<0$

$\Rightarrow (x+3)(x-1)<0$

Hence first option is correct.