wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solutions A and B are separated by a semi-permeable membrane and water moves from A to B. Hence, solution B is


A

Hypertonic

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

Hypotonic

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Isotonic

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

Hypertonic


Isotonic Solution: The relative concentration of water molecules and the solute on either side of the cell membrane is the same. Hence there is no net movement of water molecules.
Hypertonic solution: In this condition, the solution outside the cell has a higher solute concentration than the fluids inside the cell. Therefore exosmosis takes place i.e. water moves out from the cell.

Hypotonic solution: In this condition, the solution outside the cell has a lower solute concentration than the fluids inside the cell. Thus, endosmosis takes place i.e. water enters the cell and thus the cell becomes turgid.

Water always moves from a hypotonic to a hypertonic solution.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Structural Organization of Cells
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon