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Question

Solve 1+2cosecx=sec2(x/2)2.

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Solution

1+21+t22t=12(1+t2) where t=tanx2
t3+2t2+3t+2=0 or (t+1)(t2+t+2)=0
t=1 only as other factor gives imaginary values
x2=nπ+(π4)
x=2nππ2.

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