Question

Solve:$2+23x<99-x$ when $x$ is a real number.

Answer 1

$2+23x<99-x$

$\Rightarrow 2+23x+x<99-x+x$

$\Rightarrow 2+24x<99$

$\Rightarrow 2+24x-2<99-2$

$\Rightarrow 24x<97$

$\Rightarrow x<\frac{97}{24}$

$\therefore x\in (-\infty ,\frac{97}{24})$