We have nbsp; 2^2x+ 1 = 8 = gt;2^2x+ 1 = 2^3 As base is same, we can equate the powers ∴ 2x+1=3 = gt;2x=2 = gt;x=1 ...

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Comparision of Quantities Using Exponents

Solve: 22x ...

Question

Solve: $2^{2 x + 1} = 8$

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Solution

We have $2^{2 x + 1} = 8$
$=> 2^{2 x + 1} = 2^{3}$
As base is same, we can equate the powers
$∴ 2 x + 1 = 3$
$=> 2 x = 2$
$=> x = 1$

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