2cosθ 1=0 ⇒ cosθ = 1 2 ⇒θ = cos ^ 1 1 2 ⇒θ =π #160; 3 or 5π #160; 3 (in 1st and 4th quadrant respectively) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Basic Inverse Trigonometric Functions

Solve: 2cosθ...

Question

Solve: $2 cos θ - 1 = 0$

Open in App

Solution

$2 c o s θ - 1 = 0 \Rightarrow c o s θ = \frac{1}{2} \Rightarrow θ = {c o s}^{- 1} \frac{1}{2} \Rightarrow θ = \frac{π}{3} o r \frac{5 π}{3} (i n 1 s t a n d 4 t h q u a d r a n t r e s p e c t i v e l y)$

Suggest Corrections