Solve - 225 - 123 - 26

2 2 5 +1 2 3 2 6 = 12 5 + 5 3 1 3 = 12 5 + 4 3 = 36+20 15 = 56 15 ...

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Complex Numbers

Solve : 225...

Question

Solve : $2 \frac{2}{5} + 1 \frac{2}{3} - \frac{2}{6}$

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Solution

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{[1^{2} + 2^{2} + 3^{2}]}^{- 3 / 2}

- 12 - (10 \div 5) + 5 - (- 2 \times 3 + 5) + 6 - {(- 2 \times 3) \times 1 + (- 3 - 5)}

\frac{x + 5}{6} . \frac{x - 3}{9} = \frac{x + 2}{12}

x

1.) \frac{2}{3} = \frac{x}{6}

2.) \frac{- 5}{12} = \frac{15}{x}

1^{2} + 2^{2} + 3^{2} + . . . . . + n^{2} = \frac{n (n + 1) (2 n + 1)}{6}

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