Question

Solve:

$2\left[4÷\left(32+12\right)\times 5\right]-8$

Answer 1

$2[4÷(32+12)\times 5]-8$

$=2[4÷(44)\times 5]-8$

$=2(\frac{4}{44}\times 5)-8$

$2\left[\frac{5}{11}\right]-8=\frac{10}{11}-8=\frac{10-88}{11}=\frac{-78}{11}$