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B
x=−2
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C
x=1−log2log3
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D
x=2
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Solution
The correct option is Bx=−2 2x+227x/(x−1)=9 Taking log on both sides, (x+2)loge2+xx−1loge27=loge9 (x+2)loge2+3xx−1loge3=2loge3 ⇒(x+2)loge2+(x+2)x−1loge3=0 ⇒(x+2)(x−1+loge3loge2)=0 ⇒x=1−loge3loge2,x=−2