Solve: $2 x^{2} - 8 = 0$

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Solution

$2 x^{2} - 8 = 0$

$\Rightarrow 2 (x^{2} - 4) = 0$

$\Rightarrow (x - 2) (x + 2) = 0$

$∴ x = 2, - 2$

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Solve the following equation using completing the square method.

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