[ 2y^3 + y^2 2y 1; #160;= y^2( 2y + 1) 1( 2y + 1); #160;= ( y^2 1)( 2y + 1); #160;= ( y 1)( y + 1)( 2y + 1) ] ...

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Zeroes of a Polynomial

Solve 2y3+y...

Question

Solve $2 y^{3} + y^{2} - 2 y - 1$

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Solution

$\begin{matrix} 2 y^{3} + y^{2} - 2 y - 1 = y^{2} (2 y + 1) - 1 (2 y + 1) = (y^{2} - 1) (2 y + 1) = (y - 1) (y + 1) (2 y + 1) \end{matrix}$

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Similar questions

{2 y}^{3} + y^{2} - 2 y - 1

2 y^{3} + y^{2} - 2 y - 1

Factorise :
(i) $x^{3}$ −2 $x^{2}$ −x+2
(ii) 2 $y^{3}$ + $y^{2}$ −2y−1

2 y^{3} + y^{2} - 2 y - 1 = (x + a) (x - b) (c x + d)

a + b + c + d

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