Solve: $20 x^{2} - 26 x + 8$

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Solution

$20 x^{2} - 26 x + 8$
$= 2 (10 x^{2} - 13 x + 4)$
$= 2 (10 x^{2} - 5 x - 8 x + 4)$
$= 2 [5 x (2 x - 1) - 4 (2 x - 1)]$
$= 2 (2 x - 1) (5 x - 4)$

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