Solve $2 n^{2} - 13 n + 20 = 0$

Open in App

Solution

$2 n^{2} - 13 n + 20$
$= 2 n^{2} - 8 n - 5 n + 20$
$= 2 n (n - 4) - 5 (n - 4)$
$= (n - 4) (2 n - 5)$
Hence, $n = 4, \frac{5}{2}$

Suggest Corrections

Similar questions

{log}_{\frac{1}{2}} n^{2} + 1 \geq 0

2 n^{2} + n + 45 = 0

\sqrt{2} n^{2} - 3 n - 2 \sqrt{2} = 0

(x^{2} - 2 n)^{2} - 23 (x^{2} - 2 n) + 132 = 0

2 n^{2} - 11 n + 9 = 0

Join BYJU'S Learning Program