The correct option is A 19 a^3 – b^3 = (a b)^3 nbsp;+ 3ab(a b) 3^3 nbsp; 2^3 nbsp;= (3 2)^3 +3 × nbsp;3× nbsp;2×(3 2) = 1 + 18 = nbsp;19 ...

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Cube of a Number

Solve: 33-23

Question

Solve: $3^{3} - 2^{3}$

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Solution

The correct option is A
19

$a^{3}$ – $b^{3}$ = $(a - b)^{3} + 3 a b (a - b)$

$3^{3}$ - $2^{3}$ = $(3 - 2)^{3} + 3 \times 3 \times 2 \times (3 - 2)$

= $1 + 18$

= 19

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Similar questions

1^{3} + \frac{1^{3} + 2^{3}}{2} + \frac{1^{3} + 2^{3} + 3^{3}}{3} + . . .

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1^{3} + 2^{3} + 3^{3} + . . . + n^{3} = \frac{1}{4} n^{2} (n + 1)^{2}

y

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