Question

Solve $3-\left(x-5\right)=y+2$
$2\left(x+y\right)=4-3y$

Answer 1

$3-(x-5)=y+2\Rightarrow 3-x+5=y+2\Rightarrow x+y=6⟶\left(i\right)$

And $,$

$2(x+y)=4-3y\Rightarrow 2x+2y=4-3y\Rightarrow 2x+5y=4⟶\left(ii\right)$

Multiplying $\left(i\right)$ by $2$

$2x+2y=12⟶\left(iii\right)$

On substraction $\left(ii\right)$ and $\left(iii\right)$ $:$

$3y=-8$

$\Rightarrow y=-\frac{8}{3}$

Putting value of $y$ in equation $\left(i\right)$

$x-\frac{8}{3}=6$

$\therefore x=\frac{26}{3}$