Question

Solve:
$\frac{3(y-5)}{4}-4y=3-\frac{(y-3)}{2}$

Answer 1

$$\begin{gathered} \frac{3(y-5)}{4}-4y=3-\frac{(y-3)}{2} \\ \Rightarrow \frac{3y-15}{4}-4y=3-\frac{y-3}{2} \\ \Rightarrow \frac{3y-15-16y}{4}=3-\frac{y-3}{2}(\mathrm{L}.\mathrm{C}.\mathrm{M}.\hspace{0.17em}\mathrm{of}4\mathrm{and}1\mathrm{is}4) \\ \Rightarrow \frac{-13y-15}{4}=\frac{6-y+3}{2} \\ \Rightarrow \frac{-13y-15}{4}=\frac{9-y}{2} \\ \Rightarrow 2(-13y-15)=4(9-y) \\ \Rightarrow -26y-30=36-4y \\ \Rightarrow -26y+4y=36+30 \\ \Rightarrow -22y=66 \\ \Rightarrow 22y=-66(\mathrm{multiplying}\mathrm{both}\mathrm{the}\mathrm{sides}\mathrm{with}\mathrm{a}-\mathrm{ve}\mathrm{sign}) \\ \Rightarrow y=-\frac{66}{22}=-3 \\ \therefore y=-3 \end{gathered}$$