Question

Solve:
$\frac{2y+3}{3y+2}=\frac{4y+5}{6y+7}$

Answer 1

$\frac{2y+3}{3y+2}=\frac{4y5}{6y+7}$

but denominator is non $0$,

$\therefore y\ne \frac{-2}{3},\frac{-7}{6}$

$(2y+3)(6y+7)=(4y+5)(3y+2)$

$12y^2+18y+14y+21=12y^2+15y+8y+10$

$\therefore 9y=-11$

$y=\frac{-11}{9}$