Solve 350-64 - 8-7 of 4 - 6 - 2-9-1-3-

350 [64 ÷ 8 7 of {4 × 6 ÷ 2 (9 1 3)}] =350 [8 7 of {4 × 6 ÷ 2 5} =350 [8 7 of {12 5} =350 [8 7 of 7]=350 [8 49] =350+41=391. ...

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Byju's Answer

Standard VI

Mathematics

Divisibility Tests for 8

Solve 350-[64...

Question

Solve $350 - [64 \div 8 - 7$ of ${4 \times 6 \div 2 - (9 - 1 - 3)}]$

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Solution

$350 - [64 \div 8 - 7 o f {4 \times 6 \div 2 - (9 - 1 - 3)}]$
$= 350 - [8 - 7 o f {4 \times 6 \div 2 - 5}$
$= 350 - [8 - 7 o f {12 - 5}$
$= 350 - [8 - 7 o f 7] = 350 - [8 - 49]$
$= 350 + 41 = 391$ .

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(B)

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Question 7
Which constant must be added and subtracted to solve the quadratic equation $9 x^{2} + \frac{3}{4} x - \sqrt{2} = 0$ by the method of completing the square?
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(B) $\frac{1}{64}$
(C) $\frac{1}{4}$
(D) $\frac{9}{64}$

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Solve 350−[64÷8−7 of {4×6÷2−(9−1−3)}]

350−[64÷8−7 of {4×6÷2−(9−1−3)}] =350−[8−7 of {4×6÷2−5} =350−[8−7 of {12−5} =350−[8−7 of 7]=350−[8−49] =350+41=391.

Solve $350 - [64 \div 8 - 7$ of ${4 \times 6 \div 2 - (9 - 1 - 3)}]$

$350 - [64 \div 8 - 7 o f {4 \times 6 \div 2 - (9 - 1 - 3)}]$
$= 350 - [8 - 7 o f {4 \times 6 \div 2 - 5}$
$= 350 - [8 - 7 o f {12 - 5}$
$= 350 - [8 - 7 o f 7] = 350 - [8 - 49]$
$= 350 + 41 = 391$ .