Question

Solve
$3x^2-2\sqrt{6}x+2=0$ then x = $\sqrt{\frac{p}{3}}$ then p=

Answer 1

Given $3x^2-2\sqrt{6}x+2=0$

$⟹(\sqrt{3}x{)}^2-2(\sqrt{3}x\left)\right(\sqrt{2})+(\sqrt{2}{)}^2=0$

$⟹(\sqrt{3}x-\sqrt{2}{)}^2=0$

$⟹\sqrt{3}x=\sqrt{2}$

$⟹x=\sqrt{\frac{2}{3}}$