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Solving Simultaneous Linear Equation Using Cramer's Rule

Solve [3x-25...

Question

Solve
$[3 x - 2 5 x + 6 y - (2 z - y)] + 3 (z - 2 y)$

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Solution

We have,
$[3 x - 25 x + 6 y - (2 z - y)] + 3 (z - 2 y)$
$\Rightarrow [3 x - 25 x + 6 y - 2 z + y] + (3 x - 6 y)$
$\Rightarrow [- 22 x + 7 y - 2 z] + [3 z - 6 y]$
$\Rightarrow - 22 x + 7 y - 2 z + 3 z - 6 y$
$\Rightarrow - 22 x + y + z$
Hence, this is the answer.

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Similar questions

x - 2 y + 3 z = 11

3 x + y - z = 2

5 x + 3 y + 2 z = 3

Q. Solve by matrix method:

2 x + 3 y + 3 z = 5

x - 2 y + z = - 4

3 x - y - 2 z = 3

Q. Solve the following system of linear equation by matrix method

x - y + 2 z = 1

2 y - 3 z = 1

3 x - 2 y + 4 z = 2

Using matrix method, solve the system of equations 3x + 2y - 2z = 3, x + 2y + 3z = 6 and 2x - y + z = 2.

Q. Solve the following system of equations by matrix method:
(i) x + y − z = 3
2x + 3y + z = 10
3x − y − 7z = 1

(ii) x + y + z = 3
2x − y + z = − 1
2x + y − 3z = − 9

(iii) 6x − 12y + 25z = 4
4x + 15y − 20z = 3
2x + 18y + 15z = 10

(iv) 3x + 4y + 7z = 14
2x − y + 3z = 4
x + 2y − 3z = 0

(v)

\frac{2}{x} - \frac{3}{y} + \frac{3}{z} = 10 \frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 10 \frac{3}{x} - \frac{1}{y} + \frac{2}{z} = 13

(vi) 5x + 3y + z = 16
2x + y + 3z = 19
x + 2y + 4z = 25

(vii) 3x + 4y + 2z = 8
2y − 3z = 3
x − 2y + 6z = −2

(viii) 2x + y + z = 2
x + 3y − z = 5
3x + y − 2z = 6

(ix) 2x + 6y = 2
3x − z = −8
2x − y + z = −3

(x) x − y + z = 2
2x − y = 0
2y − z = 1

(xi) 8x + 4y + 3z = 18
2x + y +z = 5
x + 2y + z = 5

(xii) x + y + z = 6
x + 2z = 7
3x + y + z = 12

(xiii)

\frac{2}{x} + \frac{3}{y} + \frac{10}{z} = 4, \frac{4}{x} - \frac{6}{y} + \frac{5}{z} = 1, \frac{6}{x} + \frac{9}{y} - \frac{20}{z} = 2; x, y, z \neq 0

(xiv) x − y + 2z = 7
3x + 4y − 5z = −5
2x − y + 3z = 12

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